1. A∪B = {b, c, d, e, f, g}
A∩B = {d, f, g}
2. B' = { a, b, h , l)
From the information given, we have that:
A∪B = {The sum of sets in A and B without repetition}
Then we have:
A∪B = {b, c, d, e, f, g}
A∩B = {Sets found in both A and B}
Then, we have:
A∩B = {d, f, g}
2. B' = { sets found in the universal set and not in B}
We have:
B' = { a, b, h , l)
Thus, we can see that union and intersection of sets give different subsets from the two original sets.
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