The solution to the equation √11x + 5 = 7 is x = 4 and the solution is not an extraneous solution
How to solve for x?
The equation is given as:
The square root of the quantity 11 x plus 5 end quantity equals 7.
Rewrite as:
√11x + 5 = 7
Square both sides
11x + 5 = 49
Subtract 5 from both sides
11x = 44
Divide by 11
x = 4
Hence, the solution to the equation √11x + 5 = 7 is x = 4 and the solution is not an extraneous solution
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