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Giorgio surveyed 45 randomly selected shoppers at the mall and found that approximately 24% believe that the food court needs to be remodeled.


To the nearest percent, with a confidence level of 99% (z*-score 2.58), what is the confidence interval for the proportion of shoppers who believe the food court needs to be remodeled?


E = z* and C = + E


between 8% and 40%

between 15% and 33%

between 16% and 24%

between 21% and 69%

Respuesta :

ogorwyne

From the survey of the randomly selected shoppers the number of people that have to be surveyed would be given to be between 8% and 40%.

How to solve for the people that would have to be surveyed

The value of the sample space = (S)= 45

Confidence Level = 99%

24 percent of 45

= 0.24 * 45

= 10.8

= 11

people that support that it should be remodeled

= 10.8/45

= 0.24

z*-score 2.58

= 0.25 ± 0.25(1-0.25)/45

= 0.25 ± 0.17

= 0.08 and 0.42

This would be between 8% and 40%

Read more on confidence interval here:

https://brainly.com/question/6560782

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