The x-intercept of the line containing the points (-6, 10) and (12,-2) is; 22/3.
It follows from the task content that the points given are collinear and hence, they lie on the line whose slope can be determined as follows;
Slope, m = (-2-10)/(12-(-6))
m = -3/4.
Hence; the x-intercept can be evaluated as;
-3/4 = (0-10)/(x-(-6))
-3x -18 = -40
-3x = -22
x = 22/3.
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