By holding a positive charge and there are positive charges of equal magnitude 1 m to your north and 1 m to your east. Therefore, the direction of the force on the charge you are holding will be to the southwest.
Let I hold the charge , q at the centre of given co-ordinate system and two positive charge of equal magnitude Q are placed 1 m to my North and 1 m to my South .
now, both the charge are same nature e.g., positive . Let my charge is also positive (well, you can assume negative too , I am considering positive because it makes me easy to solve) then, both charge repel to my charge.
charge Q placed on east is repelling my charge q toward west . similarly charge Q placed on North is repelling my charge q toward south.
Now , use vector for solve it.
vector [tex]F_{net}[/tex] = vector Fe + vector Fn,
⇒ |[tex]F_{net}[/tex]| = [tex]\sqrt{} F^{2} _{e } + F^{2}_n[/tex]
⇒ Fe = Fs = KqQ/(1m)² = KqQ
⇒ [tex]F_{net}[/tex] = √{Fe² + Fs²} = √{(kqQ)²+(KqQ)²}
⇒ [tex]F_{net}[/tex]= √2KqQ
Hence, net force act on q {my charge } is √2KqQ and the direction of force is S - W (southwest )direction.
To learn more about positive charges here
brainly.com/question/2903220
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