A person borrows Rs. 19,682 9 installments and pays back in 9 installment each being treable of the preceding one. Find the first and the last installments.​

Respuesta :

The first installment is of Rs 2 and last is of Rs 13122 calculated using the geometric Series Formulae.

Let us take x as the first installment.

The second installment will be 3x as per the given statement in the question.

So likewise the installment will be increasing 3 times each in every installment. It forms geometric series.

[tex]x+3x+9x+12x.....+3^{9-1}[/tex]= 19682----------Eq 1

[tex]x(1-3^{9} )/1-3[/tex] =19682

Sum : Sn= a1 (1-[tex]r^{n}[/tex])/(1-r)

               = x(1-[tex]3^{9-1}[/tex])/1-3

                Taking - sign common from it

                = [tex]3^{9} -1 /2=19682[/tex]

                 9841 x=19862

                  x=2

According to the last term in the Eq 1 it is equal to = [tex]3^{9-1} .2[/tex]=13122

So the first installment is of Rs 2 and last is of Rs 13122.

You can find more about geometric series: https://brainly.com/question/10727576

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