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Please Help! A 200 g toy car is sliding along a frictionless track. At the top of a hill with a 0.50 m radius of curvature, the car experiences a normal force of 0.80 N. If it then descends 2.0 m to the end of the race track, what speed does it cross the finish line at?

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onyebuchinnaji

The speed with which the car crosses the finish line is 6.26 m/s.

Speed of the ball after crossing the finish line

Apply the principle of conservation of energy and determine the speed of the ball.

K.E (bottom) = P.E (top)

¹/₂mv² = mgh

v² = 2gh

v = √2gh

where;

  • h is the height traveled by the car
  • g is acceleration due to gravity
  • v is the speed of the ball at bottom of the incline

v = √(2 x 9.8 x 2)

v = 6.26 m/s

Thus, the speed with which the car crosses the finish line is 6.26 m/s.

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