In the reaction 0.867 moles of ammonia will be produced from 1.30 mol of hydrogen and excess nitrogen, because,
Hydrogen gas is oxidized by hydrogenase and electrons are carried to the anode. In the other, electrons come off the cathode and are combined with nitrogen, via nitrogenase, to create ammonia.
3H2(g) + N2(g) ⇄ 2NH3(g)
Assuming N2 is in excess, multiply the given moles H2 by the mole ratio between H2 and NH3 in the balanced equation so that moles H2 cancel, leaving moles NH3.
1.30 mol H2 × (2 mol NH3/3 mol H2) = 0.867 mol NH3.
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