The width of the frame is 6 inches.
For given question,
A rectangular painting measures 11 inches by 20 inches.
Let l represents the length of the painting and w represents the width of the painting.
⇒ l = 20 inches , w = 11 inches
A frame of uniform width around the four edges.
Let x be the width of the of the frame.
So, the length of the painting with frame would be (20 + x) inches
and the width of the painting with frame would be (11 + x) inches.
The perimeter of the rectangle formed by the painting and its frame would be,
⇒ P = 2 × [(20 + x) + (11 + x)]
⇒ 86 = 2 × (31 + 2x)
⇒ 43 = 31 + 2x
⇒ 12 = 2x
⇒ x = 6 inches
Therefore, the width of the frame is 6 inches.
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