can someone pleaseeee help me with this i need it done

The domain is -∝ < x < ∝, the range is g(x) > 0, and the asymptote is g(x) = 0
The exponential equation is given as:
g(x) = 3^(x+2)
Next, we plot the graph using a graphing calculator
See attachment for the graph of the function g(x) = 3^(x+2)
The function can take any value of x.
So, the domain is -∝ < x < ∝
Also, we have
g(x) = 3^(x+2)
Rewrite as:
g(x) = 3^x * 3^2
Set the exponent to 0
g(x) > 0 * 3^2
This gives
g(x) > 0
So, the range is g(x) > 0, and the asymptote is g(x) = 0
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