Please help me with this

a. f(g(0) = 36
b. g(f(0) = -32
From the information given, we have;
a. To find f(g(0)
Let's find g(0), that is, the value of x is substituted as 0
g(x) = 4 - x²
g(x) = 4 - (0)²
g(x) = 4
For f(g(0), the value of x is 4
f(x) = 7x + 6
f(g(0) = 7( 4) + 6
f(g(0) = 28 + 6
f(g(0) = 34
b. To find g(f(0)
Let's find g(0), that is, the value of x is substituted as 0
f(x) = 7x + 6
f(x) = 7(0) + 6
f(x) = 6
For g(f(0), the value of x is 6
g(x) = 4 - x²
g(f(0) = 4 - 6²
g(f(0) = 4 - 36
g(f(0) = -32
Thus, the value of f(g(0) and g(f(0) are 34 and -32 respectively.
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