The values of the 4 consecutive even integers that sum to –28 are; -10, -8, -6 and -4 respectively.
Even integers can be represented by 2x.
Where x is the unknown.
To get consecutive even integers, we add 2 to the previous integer.
Hence;
The consecutive numbers will be;
2x, ( 2x + 2 ), ( 2x + 4 ), ( 2x + 6 )
Given that;
Now, we add the 4 4 consecutive even integers and equate it to -28.
2x + ( 2x + 2 ) + ( 2x + 4 ) + ( 2x + 6 ) = -28
Solve for x
2x + 2x + 2x + 2x + 2 + 4 + 6 = -28
8x + 12 = -28
8x = -28 - 12
8x = -40
x = -40/8
x = -5
We plug in the value of x and the value of the integers,
2x = 2(-5) = -10
( 2x + 2 ) = ( 2(-5) + 2 ) = -10 + 2 = -8
( 2x + 4 ) = ( 2(-5) + 4 ) = -10 + 4 = -6
( 2x + 6 ) = ( 2(-5) + 6 ) = -10 + 6 = -4
The values of the 4 consecutive even integers that sum to –28 are; -10, -8, -6 and -4 respectively.
Learn more about consecutive integers here: https://brainly.com/question/15340154
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