Expressions for (s-r) (x) is -2x-3 and (s+ r)(x) is 4x-1 and evaluate (s .r) (-1) is 6 using properties of functions.
There are some operations with functions :
Sum or Difference property of functions = (f+-g)(x)=f(x)+-g(x)
Product property = (f g)(x)=f(x).g(x)
Since r(x)=3x+1
s(x)=x-2
We have to find that
(s-r)(x)=s(x)-r(x)=x-2-(3x+1)
=-2x-3
(s + r)(x)=s(x)+r(x) = (x-2)+(3x+1)
=x-2+3x+1
=4x-1
(s . r)(-1) = (x-2)(3x+1)
=[tex]=3x^{2} +x-6x-2\\=3x^{2} -5x-2\\=3.-1^{2} -5(-1)-2\\=3+5-2=6[/tex]
Hence the required values are obtained.
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