Suppose that the functions and s are defined for all real numbers x as follows.
r(x) = 3x+1
s(x)=x-2
Write the expressions for (s-r) (x) and (s+r)(x) and evaluate (s.r) (-1).
(sr)(x) = [
(s+r)(x) = [
(sr)(-1) =
X
S

Suppose that the functions and s are defined for all real numbers x as follows rx 3x1 sxx2 Write the expressions for sr x and srx and evaluate sr 1 srx srx sr1 class=

Respuesta :

Expressions for (s-r) (x) is -2x-3 and (s+ r)(x) is 4x-1 and evaluate (s .r) (-1) is 6 using properties of functions.

There are some operations with functions :

Sum or Difference property of functions = (f+-g)(x)=f(x)+-g(x)

Product property = (f g)(x)=f(x).g(x)

Since r(x)=3x+1

s(x)=x-2

We have to find that  

(s-r)(x)=s(x)-r(x)=x-2-(3x+1)

                       =-2x-3

(s + r)(x)=s(x)+r(x) = (x-2)+(3x+1)

                           =x-2+3x+1

                           =4x-1

(s . r)(-1) = (x-2)(3x+1)

            =[tex]=3x^{2} +x-6x-2\\=3x^{2} -5x-2\\=3.-1^{2} -5(-1)-2\\=3+5-2=6[/tex]

Hence the required values are obtained.

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