What is the area of the shape below

The area of the shape = area of the 2 rectangles + area of the 2 trapeziums = 7 ft².
Area of a trapezium = 1/2(a + b) × h, where a and b are the lengths of the bases of the trapezium and h is the height of the trapezium.
Area of a rectangle = (length)(width).
The shape is composed of two identical rectangles and 2 identical trapeziums.
Area of the 2 identical trapeziums = 2(1/2(a + b) × h)
a = 1 ft
b = 2 ft
h = 1 ft
Substitute
Area of the 2 identical trapeziums = 2(1/2(1 + 2) × 1) = 3 ft²
Area of the 2 identical rectangles = 2(length)(width) = 2(2)(1)
Area of the 2 identical rectangles = 4 ft²
Area of the shape = area of the 2 rectangles + area of the 2 trapeziums = 3 + 4 = 7 ft².
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