Part A
COFFEE SHOP Chenoa wants to stop for coffee on her way to school. The distance from Chenoa's house to the coffee shop is 3 miles more
than twice the distance from the coffee shop to Chenoa's school. The total distance from Chenoa's house to her school is 5 times the distance
from the coffee shop to her school.

Respuesta :

An algebraic expression is one that consists of both number(s) and an alphabet(s). The required answers are:

i. Distance from Chenoa's house to the coffee shop = 6.0 miles

ii. Distance from coffee shop to Chenoa's school = 1.5 miles

iii. Distance from Chenoa's house to her school = 7.5 miles

An algebraic expression is one that consists of both number(s) and an alphabet(s). The alphabet is referred to as the unknown whose value has to be determined.

In the given question, let the distance from the coffee shop to Chenoa's school be represented by y.

So that;

The distance from Chenoa's house to the coffee shop = (2y + 3) miles.

The total distance from Chenoa's house to her school = 5y.

This implies that:

(2y + 3) + y = 5y

3y + 3 = 5y

3 = 5y - 3y

2y = 3

y = [tex]\frac{3}{2}[/tex]

  = 1.5

The distance from the coffee shop to Chenoa's school is 1.5 miles.

Thus;

(2y + 3) = ( 2(1.5) + 3)

            = 6

The distance from Chenoa's house to the coffee shop is 6 miles.

And,

5y = 5(1.5)

    = 7.5

The total distance from Chenoa's house to her school is 7.5 miles.

For more clarifications on algebraic expressions, visit: https://brainly.com/question/12792264

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