The change in potential energy when the block falls to ground is -480J.
The maximum change in kinetic energy of the ball is 480 J.
The initial kinetic energy of the ball is 0 J.
The final kinetic energy of the ball is 0.148J.
The initial potential energy of the ball is 0.187 J.
The final potential energy of the ball is 0 J.
The work done by the air resistance is 0.039 J.
Change in potential energy when the block falls to ground
ΔP.E = -mgh
ΔP.E = -Wh
ΔP.E = - 40 x 12
ΔP.E = -480 J
Maximum change in kinetic energy of the ball
ΔK.E = - ΔP.E
ΔK.E = - (-480 J)
ΔK.E = 480 J
Initial kinetic energy of the ball
K.Ei = 0.5mv²
where;
- v is zero since it is initially at rest
K.Ei = 0.5m(0) = 0
Final kinetic energy
K.Ef = 0.5mv²
K.Ef = 0.5(0.0091)(5.7)²
K.Ef = 0.148 J
Initial potential energy of the ball
P.Ei = mghi
P.Ei = 0.0091 x 9.8 x 2.1
P.Ei = 0.187 J
Final potential energy
P.Ef = mghf
P.Ef = 0.0091 x 9.8 x 0
P.Ef = 0
Work done by the air resistance
W = ΔE
W = P.E - K.E
W = 0.187 J - 0.148 J
W = 0.039 J
Learn more about potential energy here: https://brainly.com/question/1242059
#SPJ1
