2.
Bilal is making sets of three candles.
He puts a white candle, a silver candle and
a gold candle into each set.
The candles are sold in packets of different sizes.
There are
con
25 white candles in a packet
12 silver candles in a packet
and 8 gold candles in a packet.
Bilal wants to use all the candles he buys.
(i) What is the smallest number of packets of white candles, of silver candles and of gold
candles he needs to buy?

Respuesta :

Answer:

Step-by-step explanation:

For the first part of this problem, you want to find the least common factor of the three numbers provided.

You can do it the slow way or the fast way.

The slow way is listing the factors of each number until you find the smallest number that all 3 lists have in common. E.g.,

8, 16, 24, ... 600

12, 24, 36, ... 600

25, 50, 75, ... 600

Or, the fast way involves breaking each number into prime factors, then selecting each factor that appears once or more. If a factor appears more than once, select that factor in the instance in which it has the highest exponent. Then, multiply the factors you selected.

So,

8 = 2 * 2 * 2 or 2^3

12 = 2 * 2 * 3 or 2^2 * 3

25 = 5 * 5 or 5^2

So, our LCF = 2^3 * 3 * 5^2 = 8 * 3 * 25 = 600.

Note, even though 2 appears in both 8 & 12, I selected 2^3 because 12 can gain a two faster than 8 can lose a two.

In order to have 600 white, silver, and gold candles, Bilal must buy

600/25 or 24 packets of white candles

600/12 or 50 packets of silver candles

600/8 or 75 packets of gold candles

With 600 of each candle, he can make 600 sets of candles.