Respuesta :
42.24 ppm is the solubility of O₂ in water at 25°C.
What is Henry Law constant ?
The gas law that states that if the constant is in terms of solubility or pressure.
It is expressed as
[tex]S_{\text{gas}} = k_{H} \times P_{\text{gas}}[/tex]
where,
[tex]S_{\text{gas}}[/tex] = Solubility of gas
[tex]k_{H}[/tex] = Henry's Law constant
[tex]P_{\text{gas}}[/tex] = Partial Pressure of gas
Now put the values in above equation
[tex]S_{\text{gas}} = k_{H} \times P_{\text{gas}}[/tex]
[tex]= \frac{1\ \text{mol}}{756.7\ \text{L.atm}} \times 1\ \text{atm}[/tex]
= 0.00132 mol/L
Convert the solubility into 1 mg/L
Solubility in ppm = [tex]0.00132\ \frac{\text{mol}}{L} \times \frac{32\ g}{\text{mol}} \times \frac{10^3\ mg}{1\ g}[/tex]
= 42.24 ppm
Thus from the above conclusion we can say that 42.24 ppm is the solubility of O₂ in water at 25°C.
Learn more about the Henry Law here: https://brainly.com/question/23204201
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