Complete chemical equation - Al(s) + HCl(aq) → AlCl₃(aq) + H2
The balanced stoichiometric chemical equation of the following reaction is :
2Al(s) + 6HCl(aq)→ 2AlCl3 (aq) + 3H2(g)
Steps:
There are three Cl atoms on the product side and one on the reactant side. Add a factor of 3 before HCl.
Al(s)+3HCl(aq)→AlCl3(aq)+H2(g)
There are 3 H atoms on the reactant side and 2 on the product side. Change the factor from 3 to 6 before HCl and add a factor of 3 before H2.
Al(s)+6HCl(aq)→AlCl3(aq)+3H2(g)
Now we have 6 Cl on the reactant side and 3 on the product side. Add a factor of 2 before AlCl3.
Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)
There is one Al on the reactant side and two Al on the product side. Add a factor in front of Al on the reactant side. 2Al(s)+6HCl(aq)→2AlCl3(aq)+3H2(g)
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