A group of friends wants to go to the amusement park. They have no more than $210 to spend on parking and admission. Parking is $5.75, and tickets cost $29.75 per person, including tax. Which inequality can be used to determine , the maximum number of people who can go to the amusement park?

A group of friends wants to go to the amusement park They have no more than 210 to spend on parking and admission Parking is 575 and tickets cost 2975 per perso class=

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Be:

→ X = each person  (each person pay 29.75)

→ assuming this group will only use 1 car to park, this group will pay 5.75 only once

So, Tickets + Parking must cost less than 210, otherwise there won't be enough money for group fun.

Then we can write:

29.75X + 5.75 ≤ 210

P.S. The maximum number of people allowed for this group will be:

29.75X ≤ 210 - 5.75

29.75X ≤ 204.25

X ≤ 204.25 ÷ 29.75

X ≤ 6.8

6 person × 29.75 = 178.5

178.5 + 5.75 = 184.25

If there are 6 people, there will be an exchange of 25.75

Answer:

29.75x + 5.75 ≤ 210

Step-by-step explanation:

Inequality symbols:

  • < means "less than".
  • > means "greater than".
  • ≤ means "less than or equal to".
  • ≥ means "greater than or equal to".

Given:

  • Maximum amount to spend = $210
  • Cost of parking = $5.75
  • Cost of ticket = $29.75 per person (inc tax)
  • Let x = maximum number of people.

Therefore, the total admission cost comprises the cost of a ticket per person plus the cost of parking:

⇒ 29.75x + 5.75

If the maximum amount of money to spend is $210, this means that the total cost is less than $210 or equal to $210.  Therefore, we should use the ≤ symbol.

Therefore, the inequality that can be used to determine the maximum number of people who can go to the amusement park is:

  • 29.75x + 5.75 ≤ 210