Very stable dihalides of the Group 3A(13) metals are known. What is the apparent oxidation state of Ga in GaCl₂? Given that GaCl₂ consists of a Ga⁺ cation and a GaCl₄⁻ anion, what are the actual oxidation states of Ga? Draw the shape of the anion, giving its VSEPR class and bond angles.

Lewis Structure is also called Electron dot structure, Lewis dot structure, Lewis dot formula which represent the valence shell electron in a molecule.

What is Oxidation State ?

Oxidation State is also known as Oxidation Number. It is defined as the atom is equal to the total number of electrons which have been removed from the element in order to form chemical bond with other atom.

Let the oxidation state of Ga in GaCl₂ be x

x + 2 × (-1) = 0

x - 2 = 0

x = +2

The oxidation state of Ga is +2.

But, GaCl₂ consist Ga⁺ cation and a GaCl₄⁻ anion. Now find the oxidation state of Ga in GaCl₄⁻.

Let the oxidation state of Ga be x

x + 4 × (-1) = -1
x - 4 = -1

x = -1 + 4

x = +3

So, in GaCl₄⁻ ions the oxidation state of Ga is +3.

Thus from the above conclusion we can say that The actual oxidation state of Ga is +2 and +3 and the shape of the molecule is tetrahedral. In this molecule bond angle is 109.5°.

Learn more about the Oxidation State here: https://brainly.com/question/8990767

#SPJ4