What will happen to a red blood cell (RBC), which has an internal ion content of about 0.9%, if it is placed into a beaker of pure water?
A) The cell would shrink because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
B) The cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the RBC.
C) The cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
D) The cell will remain the same size because the solution outside the cell is isotonic.

Question

23-08-2022
Biology

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What will happen to a red blood cell (RBC), which has an internal ion content of about 0.9%, if it is placed into a beaker of pure water?
A) The cell would shrink because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
B) The cell would shrink because the water in the beaker is hypertonic relative to the cytoplasm of the RBC.
C) The cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.
D) The cell will remain the same size because the solution outside the cell is isotonic.

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Correct option C) The cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the RBC.

Red blood cell (RBC), which has an internal ion content of about 0.9%, if it is placed into a beaker of pure water then cell would swell because the water in the beaker is hypotonic relative to the cytoplasm of the RBC .

The red blood cell has its normal volume in isotonic NaCl. Erythrocytes remain intact in NaCl 0.9%, and result as an opaque suspension. Distilled water is hypotonic to red blood cells.When blood cells reside in the intracellular and extracellular fluids are in osmotic equilibrium across the cell membrane, and there is no net influx or efflux of water.

Red blood cells placed in a solution with a higher water concentration compared to their contents such as water, will gain water by osmosis, swell up and burst.

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