Rank the members of each set of compounds in order of decreasing ionic character of their bonds. Use partial charges to indicate the bond polarity of each:
(c) SeF₄, TeF₄, BrF₃

Respuesta :

Fluorine is the most electronegative element, followed by chlorine, phosphorus, nitrogen, etc.

TeF₄> BrF₃> SeF₄

Negative ions are typically made up of atoms with strong electronegativity. Ionic compounds developed between element with vastly different electronegativity. The difference in electronegativity is exactly proportional to the percentage of ionic character. matching the Pauling En Scale for F (4.0), Se (2.55), Te (2.1) and Br (2.96) ΔE.N (Difference of electronegativity) between (Se and F = 4 – 2.55 = 1.45), (F and Te = 4 – 2.1 = 1.9), (F and Br = 4 – 2.19 = 1.81)

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