A charge of 6.0 mc is to be split into two parts that are then separated by 3.0 mm.what is the maximum possible magnitude of the electrostatic force between those two parts?

Respuesta :

The electric force between the charges is   9 * 10^9 N.

What is the electrostatic force between those two parts?

Let us imagine that the charge was split into two equal parts and we have them as q1 and q2. We can now be able too apply the formula that says;

F = Kq1 q2/r^2

K = electric constant = 9 * 10^9

q1 = 3 * 10^-3 C

q2 =  3 * 10^-3 C

r = 3 * 10^-3 m

We now have;

F =  9 * 10^9 * (3 * 10^-3 )^2/( 3 * 10^-3)^2

F =  9 * 10^9 N

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