Respuesta :
- 4 complementary chain pieces would be obtained in the tube containing ddATP.
- 3 complementary chain pieces would be obtained in the tube containing ddCTP.
This problem is based on DNA sequencing.
and we know that Sanger chain termination method is a popular method to determine the sequence of bases in DNA chain.
- In which chemically altered bases and an unknown sample of nucleotide is taken in a tube.
- Deoxyribonucleotide phosphate has phosphate, a base and deoxyribose sugar which take hydroxide group at second carbon of sugar.
- The chemically altered bases are deoxyribonucleoside triphosphate sequences that have deoxyribose sugar which has hydroxide group at third carbon also.
- So, as the deoxyribonucleoside triphosphate sequences add into a growing chain of DNA it stops the polymerization of chain.
Now,
The base sequence of the given DNA fragment is as follows :
TACAGGTTCAGT
In DNA, adenosine(A) base binds with the tyrosine(T) base.
So, ddATP which is dideoxyriboadenoside triphosphate will bind with tyrosine(T) of the given base sequence.
So, the following complementary sequence will be obtained:
TACAGGTTCAGT
- A
TACAGGTTCAGT
- AGTCA
TACAGGTTCAGT
- AAGTCA
TACAGGTTCAGT
- ATGTCCAAGTCA
Thus, 4 complementary chain pieces would be obtained in the tube containing ddATP.
Now,
In DNA, cytosine(C) base binds with the guanine(G) base.
So, ddCTP which is dideoxyribocytoside triphosphate will bind with guanine(G) of given base sequence.
So, the following complementary sequence will be obtained:
TACAGGTTCAGT
- CA
TACAGGTTCAGT
- CAAGTCA
TACAGGTTCAGT
- CCAAGTCA
Thus, 3 complementary chain pieces would be obtained in the tube containing ddCTP.
Thus from the above conclusion we can say that
- 4 complementary chain pieces would be obtained in the tube containing ddATP.
- 3 complementary chain pieces would be obtained in the tube containing ddCTP.
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