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A common method for producing a gaseous hydride is to treat a salt containing the anion of the volatile hydride with a strong acid.(b) In some cases, even as weak an acid as water can be used for this preparation if the anion of the salt has a sufficiently strong attraction for protons. An example is the production of PH₃ from Ca₃P₂ and water. Write the equation for this reaction.

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 One mole of calcium phosphide which reacts with excess of water in order to give two moles of phosphine.

Hydrogen preparation methods:

While preparing Hydrogen it involves multiple steps. Hydrogen is an unique element because of it's property of showing resemblance to both the halogens and alkali metals. It is also a reactive element which forms many hydrides and other compounds. It is found in a sufficient amount in plants and animal tissues. The hydrogen preparation methods can be given as:

  1. Preparation of hydrogen through laboratory method
  2. preparation of hydrogen through a commercial preparation method
  3. Preparation of Hydrogen in Industries

What is phosphine?

Phosphine is present in the chemical group called ‘organophosphorus’. Phosphine (IUPAC name: Phosphane) is an element which is a highly toxic gas and have some flammable properties.

     Phosphine is classified  in the pnictogen hydride section of the periodic table. Phosphine (PH₃) is essential in the biochemical cycle process, even though it possesses various critical chemical properties.

Structure of Phosphine:

  • Phosphin's lewis structure consist of 8 valence electrons.
  • Since both N (Nitrogen) and P (Phosphorous) are present in the same group in the periodic table, the structure of PH₃ is similar to that of NH₃ (Ammonia).
  • However, the electro-negativity of Phosphorus is lesser than that of Nitrogen(as we go down the group electronegativity decreases).
  • Bond angle between  H-P-H regions in the structure of Phosphine is 93.5°.
  • The bond length of P-H is 1.42 A.

Now,

   The equation of the following given reaction is :

       Ca₃P₂+6H₂O→2PH₃+3Ca(OH)₂.

since,

   One mole of calcium phosphide which reacts with excess of water in order to give two moles of phosphine.

Thus from the above conclusion we can say that,   One mole of calcium phosphide which reacts with excess of water in order to give two moles of phosphine.

Learn more about Phosphine here:https://brainly.com/question/15023535

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