To make 1000. L of bleach solution 1.69×10⁴ L of Cl₂(g) at STP will be needed .
A balance chemical equation is an equation that contain same number of atoms as well as of each element on each side of reaction.
It is ratio of mass to the volume.
Density= [tex]\frac{Mass}{Volume}[/tex]
Now,
The balanced chemical equation of preparing bleach from chlorine is as follow:
Cl₂(g) + 2NaOH(aq) → NaClO(aq) + NaCl(aq) + H₂O(l)
Now,
To calculate the Moles of NaClO in 1000L solution, first calculate it's mass.
Mass of NaClO = Density × Volume
= 1.07[tex]\frac{g}{ml}[/tex] × 1000L × [tex]\frac{1000mL}{1L}[/tex] ×[tex]\frac{5.25}{100}[/tex]
= 56175g
Now, we have to calculate moles of NaClO
Hence,
Moles of NaClO = [tex]\frac{amount of NaClO}{molar mass of NaClO}[/tex]
= [tex]\frac{56175g}{74.44\frac{g}{mol} }[/tex]
= 754.63 mol
Now,
According to the reaction number of moles of Cl₂ is equal to the number of moles of NaClO.
Hence,
moles of Cl₂ = 754.63 mol
Now , in order to calculate litres of Cl₂ at STP,
We know that
1 mol Cl₂ = 22.4 L of Cl₂
754.63 mol of Cl₂ = 754.63 mol × 22.4 L
= 1.69×10⁴ L of Cl₂
Thus from the above conclusion we can say that , to make 1000. L of bleach solution 1.69×10⁴ L of Cl₂(g) at STP will be needed .
Learn more about Balanced Chemical Equation here:https://brainly.com/question/27135494
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