A condensed electron configuration is a way to draw an orbital diagram for the last electron. For this type of diagram the core electrons are replaced with the symbol for the noble gas nearest to the element . Brackets are put around this symbol and then the outer, valence electrons are described as usual.
Now,
Condensed electronic configuration of:
Rubidium (Z=37) - [Kr]5s¹
Vanadium (Z= 23) - [Ar]4s²3d³
Cadmium (Z=48) - [Kr]5s²4d¹⁰
In periodic table, Rb occurs in period 4 and in between V and Cd it has it's outer electron in the s- subshell. Whereas Vanadium occurs in group 1 and in period 4 and it has partially filled d- orbitals and Rb occurs in period 5 but farthest the right and completely filled d- orbitals.
Hence,
Rb will be the least metallic and hence have least relative hardness and also have lowest melting point and vanadium will be the most metallic and hence have high relative hardness and also have highest melting point among the three.
hence,
The trend of relative hardness:
V > Cd > Rb
The trend of Melting point:
V > Cd > Rb
From the above conclusion we can say that,
The trend of relative hardness:
V > Cd > Rb
The trend of Melting point:
V > Cd > Rb
Learn more about Melting Point here:https://brainly.com/question/25808304
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