Compounds with nearly identical molar masses often have very different physical properties. Choose the compound with the higher value for each of the following properties, and explain your choice.(c) Boiling point: trimethylamine or propylamine

Respuesta :

n-Propylamine has higher boiling point .

As we know in case of 1 degree and 2 degree amines , the boiling point of these is higher than those of 3 degree amines .

Here , propylamine is 1 degree amine . it has two hydrogen atoms on the nitrogen atom . hence it has intermolecular hydrogen bonding , therefore the boiling point of propylamine is higher than  trimethylamine .

But in case of trimethylamine , it is a 3 degree amine . so it does not have hydrogen bond on nitrogen atom . as a result , it does not have hydrogen bonding . hence the boiling point of trimethylamine is lower than that of propylamine .

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