The rate law for this reaction 2 A + 2 B + C → D + 3E(c) will be rate of reaction = k [2A] [2B] [C].
The rate law of the reaction will be rate of reaction = k [2A] [2B] [C] where alpha and beta will be the order of reaction with respect to A and B and the addition of alpha and beta will be the total order of the reaction.
The order of the reaction is the main use of the rate law as it signifies about the concentration of the reactant and product for the reactions which may be zero or fractional sometimes.
Therefore, The rate law for this reaction 2 A + 2 B + C → D + 3E(c) will be rate of reaction = k [2A] [2B] [C].
learn more about rate law, here:
https://brainly.com/question/4222261
#SPJ4