The activation energy is lowered by 85351.23 J/mol.
The activation energy is the energy that is used to start a reaction.
In K = (In A) - (Ea / RT)
In K = (-Ea / RT) + In A
Where k = the activity constant
Ea = activation energy
R = molar gas constant
T = absolute temperature in Kelvin
In K₁ = (-Ea₁ / RT) + In A (eqn 1)
At point 2 with the catalyst
In K₂ = (-Ea₂ / RT) + In A (eqn 2)
Note that the molar gas constant, the absolute temperature in Kelvin, and the activity constant are all the same for both points.
Subtract (eqn 1) from (eqn 2)
In K₂ - In K₁ = (-Ea₂ / RT) - (-Ea₁ / RT) + In A - In A
In (K₂ / K₁) = (1/RT) (Ea₁ - Ea₂)
We were told that K₂ / K₁ = 2.3 × 10¹⁴, then find the difference in Ea
R = 8.314 J/mol.K, T = 37°C = 310.15 K
In (2.3 × 10¹⁴) = (1/ (8.314×310.15) (Ea₁ - Ea₂)
33.1 = (1/2578.5871) (Ea₁ - Ea₂)
(Ea₁ - Ea₂) = 33.1 × 2578.5871 = 85351.23 J/mol
Thus, the enzyme that lower the Ea is 85351.23 J/mol.
To learn more about activation energy, refer to the below link:
https://brainly.com/question/15114573
#SPJ4
