The required reaction table for the given reaction is:
{PCl}_5PCl ⇄ 5{PCl}_3PCl 3+ \{Cl}_2+Cl 2
I 0.075 \ \{M}0.075 M 00 00
C -x−x +x+x +x+x
E 0.075 \ \{M} - x0.075 M−x xx xx
What is equilibrium concentration?
When the products and reactants do not alter over time, we say that a chemical is in equilibrium concentration. In other words, a chemical reaction enters a state of equilibrium or equilibrium concentration when the rate of forward reaction equals the rate of backward reaction.
STEP 1
PCl 5(g)⇌PCl 3(g)+Cl 2 (g)
STEP 2
solve for the molarity of our reactant \text{PCl}_5PCl 5
[\{PCl}_5]=\dfrac{0.15 \ \{mol}}{2.0 \ \{L}}=0.075 \ \t{M}[PCl 5 ]= 2.0 L
0.15 mol =0.075 M
In constructing our table, we must show the initial, change, and equilibrium concentration of each reaction component.
{PCl}_5PCl ⇄ 5{PCl}_3PCl 3+ \{Cl}_2+Cl 2
I 0.075 \ \{M}0.075 M 00 00
C -x−x +x+x +x+x
E 0.075 \ \{M} - x0.075 M−x xx xx
To know more about equilibrium concentration from the link given below,
https://brainly.com/question/13414142
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