The concentration of [NO]=3.5×10−3M when a mixture of 0.20 mol of N₂(g) and 0.15 mol of O₂(g) reach equilibrium in a 1.0-L container at 2000°C
What is equilibrium?
The balance of chemicals Chemical equilibrium refers to the situation in which the reactants and products are present in concentrations that are stable throughout time and do not change the system's properties in any way that can be seen.
Step 1
In this exercise, we must determine the NO concentration in the equilibrium state of the reaction shown below
N 2 (g)+O 2 (g)⇌2N(g)
where constant Kc is 4.10 times 10-4 K.
c =4.10×10 −4
at T=2000, text C, and T=2000 ∘ C.
Step 2
In this exercise, we must determine the NO concentration in the equilibrium state of the reaction shown below
N 2 (g)+O 2 (g)⇌2NO(g)
where K c is 4.10 times 10-4 K. c =4.10×10 −4
at T=2000, text C, and T=2000∘ C.
Step 3
Calculate the reaction's component concentrations.
[N 2 ]= 1.0 L 0.20 mol =0.20 M
[H 2 ]= 1.0 L
0.15 mol =0.15 M
Step 4
Kc 4.10×10−4
4.10×10−4x2x2xx=[N][H2][NO]2=[0.20−x][0.15−x][2x]2=(0.20)(0.15)4x2=4
(4.10×10−4)(0.20)(0.15)=3.075×10−6
3.075×10−6=1.75×10−3
Kc[N2]
both >400 and O 2]K c>400
Kc[O2]>400
Step 5
Now, find [text NO 2].
[NO2
Utilizing xx.
{NO} 2]=2x=2
(1.75 times 10-3), or "boxed," equals 3.5 times 10-3.
[NO2]=2x=2(1.75×10−3)=3.5×10−3
Result
Step 6
[NO]=3.5×10−3M
Thus the concentration of [NO]=3.5×10−3M at given conditions.
To know more about equilibrium from the link given below,
https://brainly.com/question/517289
#SPJ4
