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36 ml of NaOh and 464 ml of HCOOH would be enough to form 500 ml of a buffer with the same pH as the buffer made with benzoic acid and NaOH.
What is benzoic acid found in?
- Some natural sources of benzoic acid include: Fruits: Apricots, prunes, berries, cranberries, peaches, kiwi, bananas, watermelon, pineapple, oranges.
- Spices: Cinnamon, cloves, allspice, cayenne pepper, mustard seeds, thyme, turmeric, coriander.
Calculate the amount of moles in NaOH and benzoic acid. This calculation is done by multiplying molarity by volume.
Amount of moles of NaOH -2 × 0.025 = 0.05 mol
Amount of moles of benzoic acid 2 × 0.475 = 0.095 mol
In this case, we can calculate the pH produced by the buffer of these two reagents, as follows
[tex]pH = pKa + log\frac{base}{acid}[/tex]
[tex]4.2 + log\frac{0.05}{0.045} = 4.245[/tex]
We must repeat this calculation, with the values shown for HCOOH and NaOH. In this case, we can calculate as follows
[tex]pH = pKa + log\frac{base}{acid}[/tex]
[tex]4.245 = 3.75 + log\frac{base}{acid}[/tex]
[tex]log\frac{base}{acid} = 0.5[/tex]
[tex]\frac{base}{acid} = 3.162[/tex]
Now we must solve the equation above. This will be done using the following values
[tex]\frac{2(0.5 - x)}{0.2x - 2(0.5 - x)} = 0.464 L[/tex]
With these values, we can calculate the volumes of NaOH and HCOOH needed to make the buffer.
NaOH volume
( 0.5 - 0.464)L
0.036L .................... 36ml
HCOOH volume
500 - 36 = 464mL
Learn more about benzoic acid
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