Respuesta :

21.3 KJ/mol  is the ( ΔH°vap ) of a liquid.

The Clausius - Clapeyron equation -

  • The Clausius - Clapeyron equation relates the heat of vaporization and vapor pressure.
  • The Clausius Clapeyron equation is shown below in a form similar to a linear equation (y=mx+b).
  • Vapor pressure rises non-linearly as temperature rises since the y-term in this case is a natural log of the vapor pressure

T1 = 85.2 oC

=(85.2 + 273)K

= 358.2 K

T2 = 95.6 oC

=(95.6 + 273)K

= 368.6 K

P1 = 6.21 * 10^2 torr

P2 = 7.6 * 10^2 torr

use

ln(P2/P1) = (ΔH/R) * (1/T1 - 1/T2)

ln(7.6 * 10^2/6.21 * 10^2) = (  ΔH/8.314) * (1/358.2 - 1/368.6)

0.202 = (ΔH/8.314) * (7.877 * 10^-5)

ΔH = 21320 J/mol

= 21.3 KJ/mol

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