Iodine gas and potassium bromide are created when bromine gas combines with potassium iodide. It has a harsh saline taste and hygroscopic white crystals when anhydrous.
KI + Br2 = KBr + I2
KI (aq) Potassium iodide + BaBr2 KBr (aq) Potassium bromide + BaI 2 (aq) (s) Bromine barium Potassium bromide + barium iodide equals KBr (aq), as opposed to KI (aq), which is potassium iodide plus barium bromide. The table makes it obvious that the bromine and iodine atoms are out of equilibrium.
In the described reaction, barium iodide and potassium bromide combine to generate barium iodide and potassium bromide. KBr (aq) Barium iodide + potassium bromide + BaI 2 (aq) KI (aq) Potassium iodide and barium bromide (BaBr 2(s)) KBr (aq) Barium iodide + Potassium bromide = KI (aq) Potassium bromide + BaI 2 (aq) Barium iodide.
(KI and KBr are both colorless; Br2 and I2 are the only ones with color.) Contrary to popular belief, displacement reactions take happen when a more reactive ingredient removes a less reactive element from a solution.
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