The balanced equation: 2KClO3 ----> 2KCl + 3O2
If X represents the starting mass of KClO3, then the mass of KCl in the combination is equal to
0.950 -X.
Given that the total solid mass following the reaction is 0.740g, the mass of KCl produced by the reaction is equal to this quantity less the beginning mass of KCl (0.950g - X).
In order to create one gramme of KCl, 1.644 grammes of KClO3 must be produced (formula mass KClO3/formula mass KCl),
hence the beginning mass of KClO3 is provided by 1.644 x [0.740 - (0950 - X)] which is equal to X. (initial mass of KClO3).
For X, resolve the following equation:
0.530 g KClO3 = 1.644 x [0.740 - (0.950 - X)] = X
Mass % = 0.530g /0.950 x 100 = 55.8%
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