The solubility of KCl is 3.7 M at 20°C. Two beakers contain 100. mL of saturated KCl solution: 100. mL of 6.0 M HCl is added to the first beaker and 100. mL of 12 M HCl to the second.(a) Find the ion-product constant of KCl at 20°C.

Respuesta :

The ion product constant of KCl at 20°C is 13.69

Steps

The equilibrium equation for solubility for KCl is

KCl(s)  ⇄  K⁺(aq)  +  Cl⁻(aq)

The ion-product constant is written as follows because 3.7M KCl contains equal moles of K ions and Cl ions.

Ksp = [K⁺][Cl⁻]

      = [3.7][3.7]

      = 13.69

What is an example of solubility?

A typical illustration of a solution is the addition of sugar cubes to a cup of tea or coffee. Solubility is a quality that aids in the dissolution of sugar molecules. Thus, the ability of a substance (solute) to dissolve in a specific solvent can be defined as solubility.

How may solubility be affected?

Temperature and pressure are the two direct variables that impact solubility. Pressure solely influences the solubility of gases, but temperature affects the solubility of both solids and gases.

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