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A long glass tube, sealed at one end, has an inner diameter of 10.0 mm. The tube is filled with water and inverted into a pail of water. If the atmospheric pressure is 755 mmHg, how high (in mmH₂O) is the column of water in the tube (d of Hg = 13.5' g/mL ; d of H₂O = 1.00' g/mL).

Respuesta :

This problem can be solved by referring to density and atmospheric pressure of a substance.

Given,

Inner diameter of long glass tube d(in) = 10.0 mm

The height of the mercury column h (hg) = 755 mmHg

The density of water = 1.00 g/mL

The density of mercury = 13.5 g/mL

The expression for the height of the column of water in the tube is given as-

h(H₂O) / h (hg) = Density (Hg) / Density (H₂O)

h(H₂O) = Density (Hg) × h (hg) / Density (H₂O)

Substituting the given values in above expression, we will get-

h(H₂O) = (13.5 g/mL × 755 mm) / 1.00 g/mL

           = 10192.5 mm

Thus, the height (in mm H₂O) in the column of water in the tube is 10192.5 mm.

Learn more about Atmospheric pressure here-

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