ΔS°rxn of the reaction is -242.4J/K
Chemical equation for formation of CH3OH from its elements is shown below. S°rxn is equal to S°f(products) - S°f (reactants) Here, a negative value denotes a drop in entropy during the reaction. This is in line with what we should anticipate from a reaction when two gases come together to form a single solid product. Entropy is represented by the letter S, while a change in entropy is represented by "delta" S or S. S is positive if the entropy of the system rises. S is negative when a system's entropy declines.
C+ 2H2 +1/2O2 ----> CH3OH(l)
S° (CH3OH) = 127 J/mol.K
S° (C) = 5.686J/mol.K
S° (H2) = 130.6J/mol.K
S° (O2) = 205 J/mol.K
ΔS°rxn =ΔS°rxn(products) -ΔS°rxn(reactants)
ΔS°rxn=-242.4J/K
Therefore,ΔS°rxn of the reaction is -242.4J/K
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