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A reaction that occurs in the internal combustion engine is N₂(g) + O₂(g) ⇄ 2NO(g) (b) Assuming that these values are relatively independent of temperature, calculate ΔG° at 100.°C, 2560.°C, and 3540.°C.

Respuesta :

The calculated value of ΔG° at 100.°C, 2560.°C, and 3540.°C are 171.34kJ , 110.34kJ, and 86.03kJ respectively.

In an internal combustion engine (ICE), the gasoline is ignited and burned inside the engine itself. The energy from the combustion is then partially converted into work by the engine. A stationary cylinder and a moving piston make up the engine. we know that

ΔG°=ΔH - TΔS

for 100  = 100+273 =373K

ΔG° = 180600 -(373*24.8)

   171.34kJ

for 2560 = 2560+273 =2833K

ΔG° = 180600 -(2833*24.8)

  110.34kJ

for 3540 = 3540+273 =3813K

ΔG° = 180600 -(3813*24.8)

   86.03kJ

all ΔG° value is 171.34kJ , 110.34kJ, and 86.03kJ respectively.

so the reaction is not spontaneous different temperature.

Learn more about ΔG° here:

https://brainly.com/question/4525817

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