The mass of hydrogen peroxide will be 6.07g with0.100 L of "20 volumes hydrogen peroxide" solution
Given data
Its reaction can be written as:
[tex]2H_{2} O_{2}[/tex] ⟶ [tex]H_{2} O+O_{2}[/tex]
If [tex]H_{2} O_{2}[/tex] produces 20 volumes of [tex]O_{2}[/tex].
Then we have 40 volumes of [tex]H_{2} O[/tex] due to the stoichiometry.
We have 0.1×40=4L of [tex]H_{2} O_{2}[/tex] dissolved.
PV=nR*T
Where, P is pressure, V is volume and T is temperature.
At STP, put the value of given data in above equation.
n=101325∗ 0.004/ 8,314∗273.15
n=0.1785mol
m[tex](H_{2} O_{2} )[/tex])=nMr= 6.07g
Therefore, the mass hydrogen peroxide will be 6.07g .
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