The balanced equation is:
[tex]5Fe^{2+}+ Mno_{4} ^{-} + 8H^{+}[/tex] ⇒ [tex]Mn_{} ^{2+} +5 Fe_{} ^{3+}+ 4H_{2} O[/tex]
The unbalanced redox equation is as follows:
[tex]Fe^{2+}+ Mno_{4} ^{-}[/tex] ⇒ [tex]Mn_{} ^{2+} + Fe_{} ^{3+}[/tex]
Balance all atoms other than H and O.
[tex]5Fe^{2+}+ Mno_{4} ^{-}[/tex] ⇒ [tex]Mn_{} ^{2+} +5 Fe_{} ^{3+}[/tex]
The oxidation number of Fechanges from +2 to +3. The change in the oxidation number of Fe is 1. The change in the oxidation number of Mn is +7.
Now balance O atoms on LHS,
[tex]5Fe^{2+}+ Mno_{4} ^{-} + 8H^{+}[/tex] ⇒ [tex]Mn_{} ^{2+} +5 Fe_{} ^{3+}[/tex]
Now, balance hydrogen atoms on RHS,
[tex]5Fe^{2+}+ Mno_{4} ^{-} + 8H^{+}[/tex] ⇒ [tex]Mn_{} ^{2+} +5 Fe_{} ^{3+}+ 4H_{2} O[/tex]
This is the balanced chemical equation.
Learn more about oxidation number here;
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