Respuesta :
The reaction is given below.
[tex]$\mathrm{Cu}^{2+}(\mathrm{aq})+\mathrm{Fe}(\mathrm{s}) \rightarrow \mathrm{Cu}(\mathrm{s})+\mathrm{Fe}^{2+}(\mathrm{aq})$[/tex]
The oxidizing agent is that which shows the addition of electrons in the ion, and the oxidizing agent in this above reaction is[tex]Cu $2+$[/tex]. The reducing agent is that which presented the loss of an electron from the species, and the reducing agent in this reaction is Fe.
Therefore, the reducing agent is [tex]$\mathrm{Cu}^{2+}$[/tex]and the oxidizing agent is [tex]$\mathrm{Fe}$[/tex].
Blue copper sulphate is composed of the elements Fe and CuSO4. When a nail is maintained in it, Fe—which is more reactive than copper—displaces copper from copper sulphate and creates ferrous sulphate, which is greenish blue, and the copper—which is more reactive than copper—displaces deposits surrounding nails, giving it a reddish-brown colour.
On the Periodic Table of Elements, copper is the 29th element. It is regarded as a semi-precious, nonferrous, malleable metal with countless uses in the fields of electrical and electronics, plumbing, building construction and architecture, business, transportation, and consumer and health items.
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