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A voltaic cell consists of A/A⁺ and B/B⁺ half-cells, where A and B are metals and the A electrode is negative. The initial [A⁺]/[B⁺] is such tha21.53 A voltaic cell consists of A/A⁺ and B/B⁺ half-cells, where A and B are metals and the A electrode is negative. The initial [A⁺]/[B⁺] is such that Ecell > E°cell.(c) What is [A⁺]y[B⁺] when Ecell = E°cell ? Explain.

Respuesta :

The value of [A⁺] / [B⁺], when Ecell =E°cell is 1.

Given conditions are ,

The voltaic cell consists of A/A⁺ and B/B⁺ are half-cells.

where A and B are metals and A electrode is negative.

Also, Ecell > E°cell.

We have to find the value of [A⁺] / [B⁺] when Ecell = E°cell.

Ecell = E°cell - (0.0592/n) log Q

where Q is [A⁺]/[B⁺].

As Ecell = E°cell, then putting values in the above equation, we get

0 - (0.0592/n) log Q

or, Q = 1

or, [A⁺]/[B⁺] = 1

Therefore the value of [A⁺]/[B⁺] is 1 when Ecell = E°cell.

To learn more about the Ecell, visit: https://brainly.com/question/16640433

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