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A voltaic cell with Ni/Ni²⁺ and Co/Co²⁺ half-cells has the following initial concentrations: [Ni²⁺] = 0.80 M; [Co²⁺] = 0.20 M.(b) What is [Ni²⁺] when Ecell 1 reaches 0.03 V?

Respuesta :

The concentration of the nickel ion is 0.20 M

Using the Nernst equation, we can write as follows;

Ecell= E0 cell-0.0592/n logQ

Ecell=0.03-0.0592/2 log[Cu^2+]/[Ni^2+]

0.03=0.03-0.0296 log 0.20M/[Ni^2+]

0=log 0.20M/[Ni^2+]

10^0=1=0.20M/[Ni^2+]

[Ni^2+]=0.20 M

So the concentration of [Ni^2+] is 0.20 M

  • A Voltaic Cell is defined as a galvanic cell which is also an electrochemical cell that uses spontaneous redox reactions to generate electricity. It consists of two separate half-cells.
  • A half-cell is composed of an electrode containing a strip of metal M within a solution containing M^n+ ions in which M is any arbitrary metal.

To learn more about voltaic cells visit:

brainly.com/question/1370699

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