A voltaic cell consists of two Sn/Sn²⁺ half-cells, A and B. The electrolyte in A is 0.13 M Sn(NO₃)₂. The electrolyte in B is 0.87 M Sn(NO₃)₂. Which half-cell houses the cathode? What is the voltage of the cell?

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23-08-2022
Chemistry

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A voltaic cell consists of two Sn/Sn²⁺ half-cells, A and B. The electrolyte in A is 0.13 M Sn(NO₃)₂. The electrolyte in B is 0.87 M Sn(NO₃)₂. Which half-cell houses the cathode? What is the voltage of the cell?

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rafikiedu08 rafikiedu08 · Answer 1 · 2022-08-27T06:37:49+02:00

The voltage of the cell is 0.024 V and the cathode is half cell B

In a concentration cell, the cathode is the electrode with the more concentrated electrolyte solution. Half-cell B contains 0.87V of electrolyte, while half-cell A only has 0.13V. Half-cell B is the cathode.

To compute the voltage of the cell, the concentration of these half-cells must be used in the equation

Ecell= E0 cell-RT/nf ln(anode)/(cathode)

E0cell= E0(cell) -0.0591/n ln(anode)/cathode

E0(cell)=0 n=2, we get

Ecell=0-0.0591/2 ln 0.13/0.87

Ecell=0.024 V

What is a voltaic cell?

A Voltaic Cell is a galvanic cell which is an electrochemical cell that uses spontaneous redox reactions to generate electricity.
It consists of two separate half-cells.

A half-cell is composed of an electrode containing a strip of metal M within a solution containing M^n+ ions in which M is any arbitrary metal.

To learn more about voltaic cells visit:

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