Respuesta :
When 0.10 g of ice is cooled from 10.°C to -75°C, q required is 17.74 Joules.
The heat required, q, is equal to the Specific Heat Capacity, C, times the amount of the substance times the temperature change, that is (T final - T initial) in degrees C or K.
(Remember, a difference in temperature on the C scale is equivalent to that same amount on the Kelvin scale.)
So we have, q = C x m x (T final - T initial).
Now, (T final - T initial) = (-75 C) - (10 C) = -85 C = - 85 K
(Remember, a difference in temperature on the C scale is equivalent to that same amount on the Kelvin scale. So either convert T final and T initial in K then take difference we will get same value.)
So,
q = (2.087 J/gK) (0.10 g) * (-85 K) = -17.74 Joules
The negative sign means heat is taken away from the ice (that is to say, the environment is colder than the ice).
To learn more about the specific heat capacity please click on the link https://brainly.com/question/16559442
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