A balanced half reaction for the product that forms at anode is 2H₂O → O₂ + 4H⁺ + 4e⁻ and product that forms at cathode is 2H₂O + 2e⁻ → H₂ + 2OH⁻
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now write the half equation
Zn⁺² + 2e⁻ → Zn ....(1)
2H₂O + 2e⁻ → H₂ + 2OH⁻ ...(2)
From equation (1) and (2), we can say that reduction of H₂O will occur at cathode.
2Br⁻ → Br₂ + 2e⁻ ....(3)
2H₂O → O₂ + 4H⁺ + 4e⁻ ...(4)
From equation (3) and (4), we can say that oxidation of H₂O will occur at anode.
At cathode: 2H₂O + 2e⁻ → H₂ + 2OH⁻
At anode: 2H₂O → O₂ + 4H⁺ + 4e⁻
Thus from the above conclusion we can say that A balanced half reaction for the product that forms at anode is 2H₂O → O₂ + 4H⁺ + 4e⁻ and product that forms at cathode is 2H₂O + 2e⁻ → H₂ + 2OH⁻
Learn more about the Balanced chemical equation here: brainly.com/question/26694427
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