O₂ gas formed at anode and hydrogen gas formed at the cathode in the aqueous electrolysis of K₃PO₄.
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now write the equation for Electrolysis of K₃PO₄
At cathode:
K⁺ + e⁻ → K(s) Eo = - 0.44 V
2H₂O + 2e⁻ → H₂ + 2OH⁻ Eo = - 0.827 V
It is easier to reduce water than K⁺ ions, hydrogen gas formed at the cathode.
At anode:
2H₂O → O₂ + 4H⁺ + 4e⁻ Eo = -1.23 V
O₂ gas formed at anode.
Thus from the above conclusion we can say that O₂ gas formed at anode and hydrogen gas formed at the cathode.
Learn more about the Balanced chemical equation here: https://brainly.com/question/26694427
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